144 7. TOPIC AK-7
y
x
A
O
1
B
90°
90°
45°
D
O
M
Figure 7.29.
Q
z
y
r
1
r
2
O
r
3
P
r
4
Figure 7.30.
145
Table 7.1
No.
Q P M c h
Notes ?
cm N Nm N/cm cm
1
OA = 10 - - 20 - - - P
2
O1A = 20 - 100 - - - - M
3
r
1
= 20, r
2
= 30, r
3
= 40 - - 100 - - - Q
4
OC/OA = 4/5 - 200 - - 4 - c
5
OA = 100 - - 10 - - - P
6
r
1
= 15, r
2
= 50, r
3
= 20,
O
1
A=80
200 - - - - Weight of O
1
A ignored P
7
OC = OA - - - 10 3 Spring is compressed P
8
OC= = AC - 200 - 10 2 - Q
9
OA = 20 200 - - - - Weight of O
1
A ignored M
10
r
1
= 20, r
2
= = 40, r
3
= 20,
O
1
A = 100
2,000 - - - 4 - c
11
OA = 20 - - 300 - - - P
12
O
1
D = 60, AO = 20 - - 100 - - - P
13
OA = 40 - - 200 - - - P
14
OB = 2 OA 20 - - 25 3
Weights of OA and OB are
ignored; spring is stretched
P
15
AC = OC = OD 3,000 - - 250 3 Spring is compressed P
16
d
1
= 80, d
2
= 25, l
1
= 100,
l
2
= 75
5,000 - - 100 4
Weights of O
1
B and O
2
B are
ignored; spring is stretched
P
17
OA = 20 - - 200 - - - P
18
200 200 - 100 - P – weight of pulley of radius r
2
h
19
r
1
= 20, r
2
= 30, OA = 25 - - 100 - - Weight of AB is ignored
P
20
OA = AB = AC= = 50 50 100 - - - - M
21
OA = AB = AC = DC = 25 - 200 - - - - M
22
OA = 40 - - 400 - - - P
23
OC = 2 OA = 100 - 200 50 50 - - h
24
AD = OD = OB - 250 - 150 2.5 Spring is compressed Q
25
OD = DB = 0.8 AO 400 - - 120 3
Weights of AO and BO are ig-
nored; spring is stretched
P
26
OA = 25 - 500 120 - 2 Spring is stretched c
27
OB = AB - - - 180 2 - P
28
OB = 5/4 (OA) - 450 - - - - Q
29
AO = 30, BD = O
1
D - - 120 100 - - h
30
r
1
= 10, r
2
= 36, r
3
= 10,
r
4
= 20
- 600 - - - - Q
7.1 APPLICATION OF VIRTUAL DISPLACEMENTS PRINCIPLE TO PROBLEMS ON BALANCE FORCES
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