224 Submanifolds and Holonomy
Theorem 7.4.2 Let N be a complex, locally irreducible, full (proper) submanifold
of C
n
such that the normal holonomy group, which must act irreducibly by Theorem
7.4.1, is not transitive on the unit sphere of the normal space. Then there exists a
compact Lie group K, acting as the isotropy representation of an irreducible Hermi-
tian symmetric space with rank ≥ 3, such that N is locally given, around a generic
point q, as
N =
!
v∈(
ν
0
(K·q))
q
(K ·q)
v
.
Moreover, (
ν
0
(K ·q))
q
is contained in the nullity space N
N
q
of the second fundamen-
tal form
α
N
of N at q.
Proof It remains only to show that K is of Hermitian type of rank at least 3. We
may assume that the origin 0 ∈ C
n
is the fixed point of K.Ifp ∈ N, then the position
vector p, by the description given above, belongs to T
p
N.So,Jp ∈ T
p
N. Then the
orbits of the S
1
-action (t,x) → e
it
x on C
n
are tangent to N at the points in N. In fact,
d
dt
t=0
e
it
p = Jp ∈ T
p
N. This implies that N is (locally) S
1
-invariant. Let now
¯
K be
the subgroup of linear isometries of C
n
generated by K and S
1
.Then
¯
K · p ⊂ N and
so
¯
K is not transitive on the sphere, because otherwise N = C
n
. By Simons’ Theorem
3.3.7 (see Remark 8.3.5) and since K acts irreducibly, we get
¯
K = K and so K is of
Hermitian type.
The normal holonomy group of K ·q at q, restricted to the orthogonal complement
of (
ν
0
(K ·q))
q
, coincides with the normal holonomy group of N.Infact,thisisa
consequence of the fact that R
⊥
X,Y
= 0ifX is tangent to the K-orbits in N and Y is
perpendicular to these orbits (see the arguments in the proof of Lemma 7.3.5). If the
rank of the symmetric space is 2, then the normal holonomy group of the singular
orbit K ·q would be transitive (on the orthogonal complement of the position vector).
So the rank is at least 3.
From the above local theorem we obtain the following corollary in [93] for com-
plete submanifolds.
Theorem 7.4.3 (Console, Di Scala, Olmos) The restricted normal holonomy group
Φ
∗
of a complete, irreducible, full immersed complex submanifold of C
n
acts tran-
sitively on the unit sphere of the normal space. Indeed, Φ
∗
= U
k
, where k is the
codimension of the submanifold.
Proof If the normal holonomy group of N is not transitive on the unit sphere, then,
locally,
N =
!
v∈(
ν
0
(K.q))
q
(K.q)
v
,
where K acts irreducibly as in Theorem 7.4.2 (we may assume that 0 is the fixed
point of K). Recall that we assume N to be complete (not necessarily injectively
immersed). So, if p ∈ N and since N is real analytic, then the line Rp is contained in
N (that is, this line is the image, via the immersion, of a geodesic in N). In order to
simplify the notation we omit the immersion map. By construction we have T
tp
N =