The Skew-Torsion Holonomy Theorem 259
Observe from Exercise 9.7.5 that Th eorem 9 .6.7 is also valid if M is isometric to
a Lie group with a bi-invariant Riemannian metric.
From the classification o f compact isotropy irreducible spaces [338, 346] it fol-
lows that the presentation group of any of such space, which is neither isometric to
a sphere nor to a Lie group, coincides with th e identity component of the isometry
group. We have the following corollary, which explains this fact conceptually. This
question was posed by Wolf for strongly isotropy irreducible spaces and by Wang
and Z iller in general.
Corollary 9.6.8 (Olmos, Reggiani [261]) Let M = G /H be a compact, simply con-
nected, irreducible, homogeneous Riemannian manifold that is not isometric to a
sphere or to a (simple) compact Lie group with a bi-invariant Riemannian metric.
If M is isotropy irreducible with respect to the pair (G,H) (effective action; G not
necessarily connected), then G
o
= I
o
(M).
Proof Observe first that G
o
is semisimple. In fact, let D be the distribution on M
given by the tangent spaces to the orbits of the maximal abelian normal (connected)
subgroup A of G
o
and assume that A = {e}. Such a distribution must be G-invariant
and so, since the action is effective, D
q
= T
q
M for some and hence for all q ∈ M.
Then A acts transitively on M and so M is flat, which is a contradiction.
Let us endow M with a normal homogeneous metric ·,·
with respect to the
decomposition g = h ⊕h
⊥
, where the inner product on T
p
M h
⊥
is the restriction
of −B and B is the Killing form of g.
The metric ·,·
must also be G-invariant, since any element of H preserves
both h and B.SinceH acts irreducibly on the tangent space, ·,·
coincides with the
Riemannian metric ·, · on M up to homothety. Since M is G
o
-normal homogeneous,
G
o
coincides with the group of transvections Tr(∇
c
) of the canonical connection.
Note that M = G
o
/H
o
since M is simply connected,.
From Theorem 9.6.7 we know that I
o
(M)=G
o
×K,whereK is the Lie group
whose Lie algebra consists of the G
o
-invariant vector fields on M. We shall prove
that K is trivial. Let V ⊂ T
p
M be the subspace of fixed vectors of H
o
. Observe that
the evaluation at p =[e] is a bijection between the set of G
o
-invariant vector fields
on M and V. The subspace V is H-invariant and thus V = {0} or V = T
p
M.Letus
assume that V = T
p
M.ThenK acts transitively on M. Moreover, the isotropy group
of K is trivial. In fact, dimK = dimM, which implies that the isotropy group must
be finite. Moreover, since M is simply connected, the isotropy group of K must be
trivial. On the other hand, H
o
is trivial, since it acts trivially on T
p
M = V.ThenG
o
acts, as well as K, simply transitively on M.SinceK commutes with G
o
we obtain
that K G
o
and M =(G ×G)/diag(G ×G) is isometric to a compact Lie group with
a bi-invariant Riemannian metric (see Exercise 9.7.4). This is a contradiction and
hence we must have V = {0} and so K is trivial.
9.6.2 The holonomy of naturally reductive spaces
Let M = G/H be an n-dim ensional, simply con nected, irreducib le, n aturally re-
ductive space with associated na turally reductive decomposition g = h ⊕m at p =[e]