12.1 Introduction
12.2 Classification of gas turbines
12.3 Construction and plant layout with auxiliaries
12.4 Fuel and fuel systems
12.5 Gas turbine material
12.6 Advantages and disadvantages of the gas turbine plant
12.7 Method of improving output and performance
12.8 Free piston engine plant - limitation, application and advantages
12.9 Combined cycle power plants and comparison
12.10 Layout of gas turbine plant
12.11 Questions
Gas turbine is a rotary machine that uses gas as a working fluid. The basic turbine consists of a compressor, a combustor or heater and a turbine or expander as shown in the Figure 12.1. The compressor is supplied with air at ambient conditions and raises its pressure and temperature to the required limit for combustion. The compressed air enters the combustor or combustion chamber where it gets heated from the fuel burning in the combustion chamber. The combustion products (gas and air) are then expanded in the turbine, thereby doing mechanical work. The gases are then exhausted to the atmosphere, as in an open-cycle gas turbine.
Fig. 12.1 Gas Turbine: Working Principle
Simple gas turbines can be analysed using Joule or Brayton cycle. Some assumptions are made before making any attempt to analyse an ideal cycle. These assumptions are as follows:
Analysis of the cycle is carried out with the help of the above assumptions. The simple cycle with actual and ideal processes is shown in the p-V and T-s diagrams in Figure 12.2.
Fig. 12.2 Joule Cycle: Ideal and Actual Processes
Temperature increases from T1 to T2′
Pressure increases from p1 to p2.
Volume decreases from V1 to V2′.
Work done during the process,
WC = Cp (T2′ − T1) = h2′ − h1
Heat transfer is zero.
Temperature increases from T2′ to T3.
Pressure remains constant at p2′ = p3.
Volume increases from V2′ to V3.
Work done during the process
W2′ − 3 = p (V3 − V2′)
Heat transfer during the process,
QA = Cp (T3 − T2′) = h3 − h2′
Temperature decreases from T3 to T4.
Pressure decreases from p3 = p2 to p4′ = p1.
Volume increases from V3 to V4′.
Work done during the process,
WT = Cp (T3 − T4′) = h3 − h4′
Heat transfer is zero.
Temperature decreases from T4′ to T1.
Pressure remains constant at p1 = p4
Volume decreases from V4′ to V1.
Work done during the process,
W4 − 1 = p(V4′ − V1)
Heat transfer during the process,
QR = Cp (T4′ − T1) = h4′ − h1
1. Net work done/cycle
Net work done by the cycle is the difference of the turbine work and the compressor work.
Net work done = turbine work − compressor work
= heat added − heat rejected
= QA − QR
= Cp (T3 − T2′) − Cp (T4′ − T1)
= Cp (T3 − T4′) − Cp (T2′ − T1)(1)
= (h3 − h4′) − (h2′ − h1)(2)
where, h = enthalpy of the working fluid, kJ/kg
2. Work ratio
Work ratio is defined as the ratio of net work done to the turbine work (positive work).
WR = =
=
=
WR = (3)
Again, considering the isentropic processes 1–2′ and 3–4′:
WR =
Let
= = = R, say(4)
then,
WR =
WR = (5)
3. Thermal efficiency
Thermal efficiency of the cycle is given by the ratio of net work done to the heat supplied.
η =
=
=
=
= (6)
From the isentropic processes, 1–2′ and 3–4′,
R = = = = =
where β = pressure ratio =
Equation (6) can be modified as follows:
η = = =
η = (7)
= (8)
In the actual cycle, expansion and compression in the turbine are not isentropic. This means that compressor and turbine efficiencies are to be considered for the analysis of the cycle as shown in Figure 12.3.
Fig. 12.3 Joule Cycle: Actual Cycle Analysis
Considering processes 1 and 2,
Compressor efficiency,
ηC =
ηC = (9)
ηC = (10)
∴ (11)
Considering processes 3 and 4,
Turbine efficiency,
ηt =
ηt = (12)
ηt = (13)
∴ (T3 − T4′) = (14)
From Equation (11),
(T2 − T1) =
T2 =
=
= (15)
From Equation (14),
T4 = T3 − ηt (T3 − T4′)
= (16)
1. Net work done/cycle
= WT − WC
= Cp (T3 − T4) − Cp (T2 − T1)
= (h3 − h4) − (h2 − h1)(17)
In the absence of pressure losses, the pressure and ideal temperature ratios for the compressor and the turbine are the same.
2. Work ratio
Work ratio is given by the following equation.
(18)
3. Thermal efficiency
η = (19)
=
=
=
= (20)
η =
=
= (21)
=
Assuming maximum temperature ratio,
= TR and substituting in the above equation,
η =
Dividing throughout by (R − 1)
η = (22)
η = (23)
Considering Equation (19):
Work ratio,
WR =
where R =
For fixed temperature, T1 and T3, the maximum pressure ratio is given by the following equation:
> (β)max =
(24)
For maximum power output for a given plant size, the pressure ratio that gives maximum available work per kilogram of working fluid is necessary.
Net work done/kg assuming ηt = ηi = 1
= WT − WC
= Cp (T3 − T4) − Cp (T2 − T1)
=
where R =
As the lower and upper temperatures are fixed, for maximum specific output,
= 0
i.e.,
or = T1
∴ Ropt = =
But, R =
∴ (25)
Considering compressor and turbine efficiency,
(26)
Actual heat supplied per kilogram of working fluid is given by the following equation:
QA = Cp (T3 − T2) ≈ Cp (T3 − T2′)
Now, thermal efficiency is
η =
= =
As ,
η = (27)
As T1 and T3 are fixed, the only variable is pressure ratio. Hence, for maximum thermal efficiency, the above equation has to be differentiated with respect to zero.
Substituting TR = and R = we obtain,
= 0 =
Simplifying the equation,
0 =
0 =
0 =
0 =
i.e.,
i.e.,
i.e.,
i.e.,
Multiplying the above equation throughout by
i.e.,
This is a quadratic equation, and hence it can be solved as follows:
=
R =
R =
R = (28)
Hence, the optimum pressure ratio is given as follows:
=
The variation of specific output and thermal efficiency with pressure ratio can be plotted on the graph as shown in Figures 12.4 and 12.5. The optimum pressure ratio values for maximum specific output and maximum thermal efficiency are not same.
Fig. 12.4 Variation of Specific Output with Pressure Ratio
Fig. 12.5 Thermal Efficiency v/s Pressure Ratio
For practical applications, optimum pressure ratio for maximum specific output is recommended as this factor decides the plant size.
Gas turbines are classified as (i) constant pressure combustion gas turbine and (ii) constant volume combustion gas turbine.
In the case of constant volume combustion, gas turbine heat addition takes place at constant volume in the combustion chamber. As it entails valves and consequent intermittent operation, it become obsolete and is replaced by constant pressure gas turbine.
The constant pressure gas turbines work based on the following principles:
1. Direct open cycle
The direct open-cycle gas turbine is shown in Figure 12.6. In the direct open-cycle gas turbine, air enters the compressor at point 1, where it is compressed to point 2. The air then enters the combustion chamber or the reactor where it receives heat at constant pressure (ideal cycle) and emerges hot at point 3. The gas that comes out of the combustion chamber expands in the turbine to point 4. The hot exhaust mixes with the atmosphere outside the cycle and a fresh cool supply is taken in at point 1. Part of the turbine power is used to run the compressor and auxiliaries.
Fig. 12.6 Direct Open Cycle Gas Turbine
2. Indirect open cycle
An indirect open-cycle gas turbine is shown in Figure 12.7. The elements of the indirect cycle gas turbine are similar to those in the direct open cycle except that here the air is a secondary fluid that receives heat from a primary coolant in a heat exchanger. This cycle is suitable where environment concerns restrict direct air heating as in nuclear reactors, where radioactivity releases may spread to the atmosphere.
Fig. 12.7 Indirect Open Cycle Gas Turbine
3. Direct closed cycle
A direct closed-cycle turbine is shown in Figure 12.8. In the direct closed cycle, the gas coolant is heated in the reactor, expanded through the turbine, cooled in a heat exchanger and compressed back to the reactor. In this cycle, a gas other than air may be used.
Fig. 12.8 A Direct Closed-Cycle Turbine
Fig. 12.9 Indirect Closed-Gas Turbine Cycle
No effluent of radioactive gases passes into the atmosphere under normal working conditions. This cycle permits pressurization of the working fluid with consequent reduction in plant size. Helium is the most suitable working fluid in this case.
4. Indirect closed cycle
The indirect closed cycle combines the indirect open cycle and direct closed cycle in that the reactor is separated from the working fluid by a heat exchanger. The working gas rejects heat to the atmosphere via a heat exchanger as shown in Figure 12.9. The primary coolant may be water, a liquid metal or a gas such as helium.
In the gas turbine, a fraction of power developed is utilized to run compressor along with other auxiliaries. In closed-type gas turbines, the working fluid may not be air and the pressure and temperature of the working fluid are raised by means of external heating. Here, the products of combustion do not come in contact with the working fluid.
1. Turbine
Turbine drives the compressor and the generator. Both impulse and reaction-type turbines are used but with a few stages. The turbine used should be light in weight and should have high efficiency, reliability and long life. The most commonly used turbines are axial flow types.
2. Combustion chamber
Combustion of the fuel takes place in the combustion chamber. The main components of a typical gas turbine combustion chamber are shown in Figure 12.10.
Fig. 12.10 Main Components of a Gas Turbine Combustion Chamber
The air–fuel ratio used varies from 60:1 to 120:1. The fuel used may be refined kerosene. Air enters the combustion chamber at a velocity of 75 m/s. About 25 per cent of the air from the compressor is introduced directly to the fuel burner. This is known as primary air. It mixes with the atomized fuel and forms a turbulent mixture for ignition. It prevents the formation of carbon deposits over the burner tips and produces an envelope around the flame, preventing the flame from touching the walls. As the primary air is passed through swirl vanes, it causes reversal of gas flow, and hence stabilizes the flame; that is, it prevents the extinction of flame by high velocity air. The remaining air, known as secondary air, enters the annulus around the flame tube, cooling the upper portion before entering intermediate and dilution holes or openings. Any imperfectly mixed fuel-rich pockets of the gas burns in the intermediate zone which might have formed due to dissociation. The dilution zone further brings down the temperature so as to suit the operating temperature of the turbine. About 20–40 per cent of the total combustor air flow is used for this purpose. A traditional gas turbine combustor showing air and gas passages in all the three zones can be seen in Figure 12.11.
Fig. 12.11 Air and Gas Flow in a Traditional Gas Turbine Chamber
3. Compressor
Generally used pressure ratios of a gas turbine plant of high efficiency and output is 10:1 or more. For a pressure ratio of 4:1, a single-stage centrifugal compressor is generally preferred. This is because a centrifugal compressor can operate over a wide range of mass flow rate than an axial flow compressor. For higher pressure ratios instead of using multi-stage centrifugal compressors, axial flow compressors are found most suitable. For pressures ratios, more than 6:1, more than one compressor can be used. Axial flow compressors are heavier than centrifugal flow compressors but have higher efficiency. Reciprocating compressors are generally not preferred because they are heavy, slow, have more sliding parts and cannot handle large volumes of air.
A centrifugal compressor is a power-absorbing turbomachine in which the angular momentum of the fluid flowing through the impeller is increased. Fans, blowers, superchargers, boosters, etc., can be treated as centrifugal type depending on pressures and field of applications. A pressure ratio ranging from 4:1 to 6:1 can be obtained using a single-stage compressor. Even though it has high specific fuel consumption, a centrifugal compressor has the following advantages over an axial flow–type compressor:
Figure 12.12 shows centrifugal compressor stage consisting mainly of four parts:
Fig. 12.12 Section of a Centrifugal Compressor Stage
1. Impeller
Figure 12.13 shows different components of an impeller. It consists of impeller vanes, hub, shroud and an inducer.
Fig. 12.13 Impeller Components
The impeller may be either single sided or double sided. In the latter case, the fluid is drawn on both sides and the impeller is subjected to approximately equal forces in an axial direction.
2. Diffuser
The diffuser may be either vaned diffuser or vaneless diffuser. The vaneless diffuser has only the annual space without having any guide vanes. The diffuser increases the static pressure of the fluid by reducing kinetic energy.
Figure 12.14 shows the variation of pressure in a centrifugal compressor.
When air is accelerated in the nozzle next to the inlet casing, its velocity increases, while entering the impeller with corresponding drop in static pressure (a − b). In the impeller, blades impart swirling motion to air resulting in high velocity at impeller tip. Energy transfer takes place resulting in increased static pressure of air (b − c) due to centripetal acceleration. Air further enters the diffuser wherein high velocity air leaving the impeller is converted into pressure (c − d). This high-pressure air is collected in the collector or volute that delivers it.
Fig. 12.14 Variation of Pressure in a Centrifugal Compressor
Fig. 12.15 Compression Process in a Centrifugal Compressor Stage
Figure 12.15 shows the compression process in a centrifugal compressor stage. State point 01 corresponds to ambient air conditions.
As air is accelerated in the inlet casing, it causes a pressure drop from p01 to p1 or p00 to p1 assuming losses in inlet casing. The enthalpy change during this process is equal to a change in kinetic energy of processes 01–03′ shows isentropic compression corresponding to delivery stagnation pressure. Processes 1–2 and 1–2′ represent actual compression and isentropic compression in the impeller, respectively.
Pressure p02 corresponds to delivery pressure if the total kinetic energy leaving the impeller is converted into pressure. Since the diffusion process is not isentropic, the final delivery pressure is corresponding to static pressure p3. Energy corresponds to the kinetic energy in the collector. p03 < p02 as the diffusion process is irreversible.
Diffusers used in centrifugal compressors may be either vaned or vaneless. Since a considerable amount of energy is transformed in the diffuser, its efficient transformation is to be taken care of Design of diffuser is very important as losses due to flow of fluid against the adverse pressure gradient may be high.
In a vaneless diffuser, the fluid is diffused around the impeller before leaving the stage in a vaneless space. The diffuser gains static pressure rise due to diffusing action of the fluid from a small diameter to a larger diameter (d3). The corresponding area of cross section in the radial direction are as follows:
A2 = πd2b2
and A3 = πd3b3
This type of flow in a vaneless space is a free vortex flow, the angular momentum remaining constant.
Figure 12.16 shows a vaneless diffuser. It consists of an annular passage without vanes surrounding the impeller. The width of the annulus may be constant or may be tapered outwards to provide more rapid diffusion. The taper angle θ varies from 4° to 8°. Some of the disadvantages of vaneless diffuser are as follows.
However, it is used for industrial applications where large-sized compressors are needed. It is more economical and gives wider range of operation.
Fig. 12.16 Vaneless Diffuser
A schematic diagram of an axial flow compressor is shown in Figure 12.17. It consists of a number of fixed blades attached to the casing, and alternate rows of moving blades are fixed on a central drum, which rotates along with the shaft. Air progresses from one blade row to the next and is guided by the fixed blades. Fixed blades serve the function of a diffuser, and hence the pressure of air increases when it comes out of the duct. As air passes parallel to the axis of rotation of the shaft, the flow is axial, and hence the name axial flow compressor. These compressors usually run at high speed (10,000–30,000 rpm) and are used to supply large quantity of air as in aircraft gas turbines. The pressure ratio of compression may be about 10:1.
Fig. 12.17 Axial Flow Compressor with Drum-Type Rotor
Due to rapid compression, the time available for heat transfer is less and hence compression is nearly adiabatic. However, due to generation of friction and turbulence, internal energy within air generates temperature that is higher than the adiabatic temperature. Thus, the index ‘n’ is greater than adiabatic index ‘γ ’ for a rotary compressor.
Fig. 12.18 An Axial Compressor Stage
As shown in Figure 12.18, the compressor consists of alternate sets of moving and fixed blades. The sets of fixed blades that are spaced around an outer stationary casing are called stator blades, and the sets of moving blades fixed to a spindle are called rotor blades. A very small tip clearance at the end of the stator and rotor blades is provided to ensure smooth and efficient flow. A compressor stage consists of one set of stator blades and one set of rotor blades. Depending on the pressure ratio required, stage may be either single or multiple. In multistage arrangement, the successive sets of blades are reduced in length to compensate for reduction in volume resulting due to pressure increase from stage to stage.
An axial compressor may have either disc-type rotor or drum-type rotor. For the same overall weight, centrifugal stresses are lower in the disc type than in the drum type.
The basic principle of operation of an axial flow-type compressor is similar to that of a centrifugal type. Here, the rotating blades impart kinetic energy to air that is further converted into pressure rise. Stator recovers part of kinetic energy imparted to the working fluid and redirects the fluid to the rotating blades of next stage at a convenient angle. Air is guided to the rotor blades using inlet guide vanes (IGVs) as shown in Figure 12.19. Air enters the combustion chamber through one to three rows of diffuser blades or straightener blades installed after the last stage. This is to ensure that air is straightened and skewed down before it enters the combustion chamber.
Figure 12.19 shows the velocity triangles for an axial compressor stage. Subscripts 1, 2, and 3 correspond to condition of air at entry to rotor, exit from rotor and diffuser blades respectively.
Let α1, α2, α3 and β1, β2 be the air angles in the absolute and relative systems, respectively. Subscripts a and u represent axial and tangential component of absolute velocity, respectively, and ru represents tangential component of relative velocity Vr.
Fig. 12.19 The Velocity Triangles
In the case of an axial flow compressor, it is assumed that the axial velocity Va is constant throughout. In order to have this condition, it is necessary to maintain a converging area of flow as pressure increases in every stage.
Work input:
W = U (Vu2 − Vu1)
= U (Va tan α2 − Va tan α1)
W = UVa (tan α2 − tan α1)
W = UVa (tan β1 − tan β2)
From Euler's equation,
E = (V22 − V12) + (Vr12 − Vr22)
as U = constant throughout.
It can be noted that due to secondary flows and growth of the boundary layers on the hub and the casing of the compressor annulus, the axial velocity is not uniform. In a multistage compressor, this effect is considerable after the first stage and the degree of distortion depends on the number of stages. Owing to this effect, the axial velocity in the hub and tip regions is much lesser than the mean value; whereas in the central zone, it is much higher than mean value.
The work-absorbing capacity decreases with an increase in axial velocity and vice versa. Hence, the work-absorbing capacity is decreased in the central region as compared to hub and tip regions. However, the increase in work at the hub and tip regions is not expected in the actual practice due to higher losses. The net result is the work-absorbing capacity in a stage is less than that given by Euler's equation. This reduction in the work-absorbing capacity of the stage is taken into account by a factor known as work done factor, denoted by Ω. Its value ranges from 0.98 to 0.85 depending on number of stages.
Considering work done factor, work done on air is given by
W = Ω UVa (tan β1 − tan β2)
Since, W = CP ΔTs = CP (To2 − To1),
ΔTs = (tan β1 − tan β2)
Where ΔTs is the stagnation temperature rise in stage.
Therefore, work done factor is a measure of the ratio of the actual work-absorbing capacity of the stage to its ideal value.
The degree of reaction for axial compressors is given by
R =
R =
If V1 = V3, then
R =
=
In terms of air angles,
R =
R =
Substituting = = flow coefficient
tan βm = 1/2 (tan β1 + tan β2)
= mean relative air angle
then,
R = tan βm
∴ R =
Fuel supply is one of the most important factors that govern the operation of gas turbines. Fuel that mismatches with the gas turbine combustion requirements may seriously affect the operation and maintenance apart from load shedding and turbine tripping. Fuels used in gas turbines can be broadly classified as gaseous and liquid fuels:
The most commonly used gaseous fuels are the following:
The most commonly used liquid fuels are the following:
Selection of fuel influences the performance of gas turbines. In case of a simple gas turbine, natural gas yields 2–3 per cent more power when compared to distillate oil, as it has higher specific heat of combustion products due to higher hydrogen to carbon ratio (H/C ratio). Higher H/C ratio results in more water vapour formation.
Natural gas mainly contains methane and sometimes traces of ethane, propane and pentanes, which increase the heating value. Presence of inert gases such as nitrogen and carbon dioxide generally decreases the heating value. Table 12.1 list down the key properties of methane and propane.
Owing to rapid growth in liquefaction trains and worldwide shipment, LNG has become an important fuel for gas turbine operation. This is despite of LNG having traces of inert gases that reduce its heating value.
Table 12.1 Key Properties of Methane and Propane
As can be seen from Table 12.1, methane has higher heat value compared to propane towing to which it produces more water vapour and carbon dioxide, resulting in higher specific heat and hence turbine power. It can be noticed that fuels with higher hydrogen content tend to generate more power. Some gaseous fuels used for gas turbines and their heating values are given in Table 12.2.
For the land-based turbines, natural gas offers convenient delivery and handling and prefers to be continued as the fuel, by offering clean and efficient combustion properties. Due to the ‘location-specific’ availability of this fuel around the globe or due to scarcity, liquid fuels ranging from light distillates to residual grade oils or unrefined crude oils are gaining importance as alternative gas turbine fuels. Liquid distillates such as diesel oil and kerosene are also very widely used as secondary backup for gas turbine fuels in dual fuel applications. The following Table 12.3 gives the information on liquid fuels for gas turbine and their heating values.
Table 12.2 Gaseous Fuels for Gas Turbine and their Heating Values*
* Source: Beareau of Energy Efficienry.
Table 12.3 Liquid Fuels for Gas Turbine and their Heating Values [1]
Advancements made in the field of materials have contributed in a major way in building gas turbine engines with higher power ratings and efficiency levels. Improvements in design of the gas turbine engines over the years have importantly been due to development of materials with enhanced performance levels. Gas turbines have been widely utilized in power generation, industrial sector, marine and aircraft engines. In gas turbine plant major components, turbine blades in particular are critically exposed to very high temperatures continuously unlike in an IC engine. In this context, gas turbine materials should posses the following properties:
The following Table 12.4 provides the component characteristics and materials used in gas turbines.
Table 12.4 Component Characteristics and Materials Used in Gas Turbines
The following Table 12.5 provides the component characteristics and materials used in gas turbines.
Table 12.5 Component Characteristics and Materials Used in Aeroengines
Advantages over diesel plants
Smokeless combustion has been achieved by the gas turbine with proper control of primary zone mixture ratios and methods of secondary air introduction, and recirculation could produce reduced pollution conditions. It is claimed that the exhaust gases that come out are smokeless without increasing the production of nitric oxide emissions.
The disadvantages of gas turbine plants over diesel plants can be summarized as easier maintenance, improved reliability, lower initial cost, smaller plant dimensions and less space requirements for same output, less vibrations, absence of cyclic variations and greater starting torque.
The disadvantages of gas turbine plants over diesel power plants include poor part load efficiency, requirement of special metals and alloys for different components of the plants, special cooling methods for cooling the turbine blades, low starting torque and less life.
Advantages over steam power plant
Advantages
Disadvantages
The following methods are used to improve the output and performance of a gas turbine.
Plant efficiency can be improved by reheating of the gas after it expands in the high-pressure turbine as shown in Figure 12.20.
Fig. 12.20 (a) Gas Turbine Plant with Reheater (b) T-s Diagram with Reheater
For the same expansion ratio with reheating in two stages as compared to single-stage expansion, the work output will be increased as seen on the T-s diagram. Usually, the upper limit for reheating is T3 = T5.
Now, turbine work output from LP and HP turbines is
WT = Cpg (T3 − T4) + Cpg (T5 − T6)
= Cpg ηt1 (T3 − T4′) + Cpg ηt2 (T5 − T6′)
WT = (1)
where ηt1, ηt2 = HP and LP turbine efficiencies
Cpg = specific heat of the gas
For the isentropic processes 3–4′ and 5–6′,
= and =
Substituting in Equation (1) above with = x
WT = (2)
In the above equation with T3, p1 and p2 fixed, only variable is pi. Hence for maximum work output,
= 0
i. e.,
=
Hence, =
∴pi =
i. e., pi =
Hence intermediate pressure
pi = (3)
When, T5 = T3, TR = 1 and if ηt2 = ηt1,
pi = (4)
Thermal efficiency of the cycle is given by the following equation:
η =
= (5)
The thermal efficiency and specific output of the gas turbine cycle can be increased by using regeneration method. In this method, the heat in the exhaust gases is used to increase the temperature of air that comes out of the compressor. This increases the temperature of air and reduces the fuel consumption in the combustion chamber. A gas turbine plant fitted with a regenerator or heat exchanger is shown in Figure 12.21.
In perfect regeneration, under ideal conditions, temperature of compressed air that comes out of the compressor at temperature T2 is increased to T5 and temperature of air after expansion in the turbine is reduced from T4 to T6 as shown on the T-s diagram in Figure 12.22.
Thus, T5 = T4 and T6 = T2, and it can be noticed that the turbine and compressor work are unchanged.
Hence, the thermal efficiency of the cycle is modified as follows:
η = (1)
η = as T4 = T5
= (2)
=
Fig. 12.21 (a) Gas Turbine with Regenerator (b) T-s Diagram
Fig. 12.22 T-s Diagram with Regenerator
=
= ; as = TR
=
η = ; as R = (3)
From Equation (3), it is evident that as temperature ratio increases (TR), thermal efficiency of the cycle increases. Again, decreasing the pressure ratio term (R), thermal efficiency increases.
In an actual cycle, it is not possible to attain the condition T5 = T4. The actual temperature of air that comes out of the regenerator is lesser than T5 and is equal to T5′ as shown on the T-s diagram in Figure 12.22.
Hence, cycle efficiency
η = (4)
Heat exchanger efficiency or effectiveness,
η =
η = = (5)
where ma, mg = mass flow rate of air and gas, respectively, with corresponding specific heats Cpa and Cpg.
In case, ma = mg and Cpa = Cpg, then the above equation reduces to
η = (6)
Even though regenerator efficiency increases with increased heat-transfer surface area, the space and pressure loss consideration limits its use.
Another method of improving the plant efficiency is to reduce the work absorbed by the compressor stages, by adopting an intercooler in between the stages. Such an arrangement is shown in Figure 12.23.
Fig. 12.23 (a) Gas Turbine with Intercooler and (b) T-s Diagram for Perfect Intercooling
For single-stage compression, compressor work input is given by the following equation:
WC = Cp (T2′ − T1) = Cp [(T2 − T1) + (T2′ − T2)](1)
For two-stage compression, compressor work input is given by the following equation:
WC = Cp [(T2 − T1) + (T4 − T3)](2)
Comparing the above two equations, it can be noted that in the T-s diagram that
(T2′ − T2) > (T4 − T3)
Hence, work input is reduced in two-stage compression. For perfect intercooling, T3 = T1.
But in actual practice, intercooling is not perfect, and hence T3 > T1 as shown in the T-s diagram in Figure 12.24.
Fig. 12.24 Gas Turbine with Imperfect Intercooling
Considering a two stage compression, compressor work is given by
WC = Cp (T2 − T1) + Cp (T4 − T3)
=
=
WC = (3)
where ηC1, ηC2 = isentropic efficiency of first and second compressors, respectively,
pi = intermediate pressure between two stages,
Substituting = x and = TR, we get
WC = (4)
For minimum compressor work, with pressures p1 and p2 and temperatures T1 and T3 fixed, we have,
= 0
= 0
i.e., = 0
i.e., = 0
=
i.e., =
Hence, =
∴pi =
i. e., pi =
In other words, for imperfect intercooling,
pi = (5)
For perfect intercooling, TR = 1 and if ηC1 = ηC2, then
pi = (6)
Substituting this value in Equation (4) above,
For perfect intercooling,
WC = =
WC =
Thermal efficiency of the turbine is given by the following equation:
ηth =
In the above equation as WC = (T2 − T1) + (T4 − T3) reduces and turbine work WT = (T5 − T6) remains same, thermal efficiency of the cycle decreases as (T5 − T4) = heat addition increases in case of imperfect intercooling, as compared to perfect intercooling.
Example 12.1
Air is drawn in a gas turbine at 18°C and 1 Bar and leaves the compressor at 5 Bar. Data observed are the following:
Temperature of gases entering the turbine = 678°C.
Pressure loss in combustion chamber = 0.1 Bar.
ηcompressor = 85% γ = 1.4 for air
ηcombustion = 85% Cp = 1.024 kJ/kg K for gas
ηturbine = 80%
Find the (i) quantity of air, if plant develops 1065 kW; (ii) heat supplied per kg of air circulated and (iii) thermal efficiency of cycle.
Solution: The cycle is shown on the T-s diagram below.
Consider processes 1 and 2, = = = 1.584
T2 = T1 × 1.584 = 300 × 1.584 = 475.2 K.
=
T4 =
=
= 519.57 K
η =
For unit mass of air,
=
=
= 36.87%
Regenerator efficiency
=
T5′ = (T5 − T2) + T2
= 0.60 (519.57 − 475.2) + 475.2
= 26.62 + 475.2
= 501.822 K
η =
=
= 39.93%
Example 12.2
In an open-cycle constant pressure gas turbine unit air enters compressor at 1 bar and 300 K. The pressure of air after compression is 4 bar, the isentropic efficiencies of compressor and turbine are 80 per cent and 85 per cent, respectively. The air fuel ratio is 90:1. Calculate the power developed and thermal efficiency of the cycle if the flow rate of air is 3 kg/s. Take Cp = 1.005 kJ/kgK and γ = 1.4 for air and gases CV = 42,000 kJ/kg
Solution:
Temperature at the end of isentropic compression is given by
=
T2′ = (300)
T2′ = 445.8 K
Actual temperature rise during compression is
T2 − T1 = =
= 191
T2 = T1 + 178 = 300 + 191
T2 = 491 K
Heat supplied by the fuel = heat taken by the gases:
mf CV = (ma + mf) Cp (T3 − T2)
CV =
42,000 = (90 + 1) × 1(T3 − 491)
T3 =
T3 = 952.54 K
The work required to drive the compressor is
WC = CP (T2 − T1)
WC = 1.005 (491 − 300)
WC = 191.96 kJ/kg of air per sec.
Temperature at the end of isentropic expansion is
T4′ = = = 641.01 K
∴ Actual temperature drop = T3 − T4 = ηt (T3 − T4′)
= 0.85 (952.54 − 641.01) = 264.8°C
T4 = T3 − 264.8 = 952.54 − 264.8
T4 = 687.74 K
Total turbine work is
Wt = m Cp (T3 − T4)
=
Wt = 267.74 kJ/kg of air per sec
∴Net work output = WT − WC = 267.74 − 191.96
= 75.78 kW/kg of air
Net power developed by the turbine = 75.78 × 3 = 227.34 kW
Heat supplied per kilogram of air = = 466.67 kJ/kg of air
Thermal efficiency, ηt = = 16.24%
Example 12.3
In a regenerative gas turbine cycle, air enters the compressor at 1 bar 15°C. Pressure ratio = 6. The isentropic efficiencies of compressor and turbine are 0.8 and 0.85, respectively. The maximum temperature in the cycle is 800°C. The regenerator efficiency = 0.78, Assume Cp = 1.1 kJ/kgK and γ = 1.32 for the combustion products and find the cycle efficiency.
Solution: The gas turbine cycle is shown as the T-s diagram.
Pressure ratio β = = 6
p2 = 6 bar
For the actual cycle, temperature of air at the compressor exit is given by
T2 =
=
= 528.66 K
Compressor work is given by
WC = CP (T2 − T1) = 1.005 (528.66 − 288)
= 241.86 kJ/kg
Considering processes 3 and 4, the actual temperature of gases at turbine exit is given by
T4 = =
= 751.66 K
Turbine work is given by
WT = mgCpg (T3 − T4); (ignoring fuel mass, ma = mg)
= 1 × 1.1 (1073 − 751.66)
= 353.47 kJ/kg
Net work output
= WT − WC = 353.47 − 241.86
= 111.6 kJ/kg
Now, efficiency of the regenerator is given by
ϵ = ; T5 = T4 for ideal conditions
0.78 =
T5′ = 528.66 + 0.78 (751.66 − 528.66)
= 702.8 K
Thermal efficiency of the cycle, assuming ma = mg and Cpa = Cpg,
η =
=
=
= 24.49%
Considering Cpg and Cpa
η =
= 27.4%
Example 12.4
In an open-cycle gas turbine plant, air enters the compressor at 1 bar and 27°C. The pressure after compression is 4 bar. The isentropic efficiencies of the turbine and the compressor are 85 per cent and 80 per cent, respectively. Air fuel ratio is 80:1. The calorific value of the fuel used is 42,000 kJ/kg and mass flow rate of air is 2.5 kg/s. Determine the power output from the plant and the cycle efficiency. Assume that Cp and γ to are same for both air and products of combustion.
Solution:
Given data: p1 = 1 bar, T1 = 300 K
p2 = p3 = 4 bar, ηT = 0.85, ηc = 0.80
ma = 2.5 kg/s; ma/mf = 80
CV = 42,000 kJ/kg
Cp = 1.005 kJ/kgK (assumed)
γ = 1.4 (assumed)
For processes 1 and 2′,
=
T2′ = T1
= 300
T2′ = 446 K
Compressor efficiency ηc =
T2 = T1 +
∴ T2 = 300 +
T2 = 482.5 K
For processes 3 and 4′,
=
= T3 (1)
Heat supplied per unit time:
Q2 − 3 = mf CV
=
= 1312.5 kJ/s
But Q2 − 3 = (ma + mf)h3 − mah2
h3 =
T3 =
=
T3 = 992.3 K
From Equation (1),
= T3 = 992.3
= 667.5 K
Turbine efficiency is given by
ηT =
∴T4 = T3 − ηT(T3 − T4′)
T4 = 992.3 − 0.85 (992.3 − 667.5)
T4 = 716.22 K
Compressor work per unit time = WC = maCp (T2 − T1)
= 2.5 × 1.005 (482.5 − 300) = 458.53 kJ/s
= 458.53 kW
Turbine work per unit time = WT = (ma + mf) Cp (T3 − T4)
WT = (2.5 + 2.5/80) × 1.005 × (992.3 − 716.22)
= 702.32 kW
Net work output = 702.32 − 458.53
= 243.79 kW
Cycle efficiency ηcycle = =
= 18.58%
Example 12.5
A gas turbine power plant operates on ideal Brayton cycle. The minimum and maximum cycle temperature are T1 = 300 K and T3 = 800 K, respectively. Find the value of the optimum pressure ratio for maximum specific work output and the cycle efficiency for this condition. Is it possible to improve this cycle efficiency by including regenerator? Substantiate.
Solution: Given data
Tmin = T1 = 300 K
Tmax = T3 = 800 K
Optimum pressure ratio for maximum output is given by
βopt = =
= = 5.565
Cycle efficiency, η = 1 − = 1 −
η = 1 − = 38.76%
Condition for maximum work output is satisfied for
=
But =
=
T2 = T4 =
As T2 = T4, regenerator is not required.
Example 12.6
A simple gas turbine plant operating on the Brayton cycle has air entering the compressor at 10 kPa and 27°C. The pressure ratio = 9 and maximum cycle temperature = 727°C. What will be the percentage change in cycle efficiency and net work output if the expansion in the turbine is divided into two stages each of pressure ratio 3, with intermediate reheating to 727°C? Assume compression and expansion are ideal isentropic.
Solution:
Given that
p2 = 1 bar
T1 = 300 K
= 9
T3 = T5 = 1000 K
For the processes 1 and 2,
= = = 1.875
∴ T2 = T1 × 1.875 = 300 × 1.875 = 562.5 K
For the processes 3 and 4,
T4 = = = 533.3 K
Compression work, WC = CP(T2 − T1)
= 1.005 (562.5 − 300)
WC = 263.8 kJ/kg
Expansion work, WT = CP(T3 − T4)
= 1.005 (1000 − 533.3)
WT = 469.03 kJ/kg
Net work output = WT − WC
= 469.03 − 263.81 = 205.22 kJ/kg
Heat supplied QS = CP(T3 − T2)
= 1.005 (1000 − 562.5)
= 439.68 kJ/kg
Cycle efficiency (η)1 =
= = 0.4667 = 46.67%
= (3)0.286 = 1.369
T4a = = 730.4 K
As the pressure ratio in the second stage is the same and air is reheated to 1000 K,
T6 = T4a = 730.4 K
Work of expansion in each stage will be the same.
∴ Total work of expansion
WT = 2CP (T3 − T4a)
= 2 × 1.005 (1000 − 730.4)
= 541.89 kJ/kg
Work of compression will remain the same, that is, 263.81 kJ/kg.
Net work output = WT − WC
= 541.89 − 263.81
= 278.08 kJ/kg
Heat supplied QS2 = heat supplied in combustion chamber + heat supplied in the reheater
= CP(T3 − T2) + CP(T5 − T4a)
= 1.005 (1000 − 562.5) + 1.005 (1000 − 730.4)
= 439.68 + 270.94
= 710.62 kJ/kg
Cycle efficiency
η2 = = = 0.3913 = 39.13%
Percentage change in efficiency
η = =
= −16.15%
Percentage change in work output
=
= = 0.355 = 35.5%
Example 12.7
A gas turbine power plant operates on the simple Brayton cycle with air as the working fluid and delivers 32 MW of power. The minimum and maximum temperatures in the cycle are 310 K and 900 K, respectively, and the pressure of air at the compressor exit is eight times the value at the compressor inlet. Assuming an isentropic efficiency of 80 per cent for the compressor and 86 per cent for the turbine, determine the mass flow rate of air through the cycle.
Solution: Given data
= T3 = 900 K
= T1 = 310 K
rP = 8, = 0.8, = 0.86
For processes 1 and 2, T2′ = T1
T2′ = = 561.55 K
Considering compressor efficiency,
=
∴ = T1 +
= 561.55 +
= 624.44 K
For process 3 and 4,
T4′ =
=
= 496.84 K
Considering turbine efficiency,
ηT =
∴ T4 = T3 −
= 900 − 0.86 (900 − 496.84)
= 553.3 K
Compressor work is given by
WC = CP(T2 − T1) = 1.005 (624.44 − 310)
= 316.01 kJ/kg
Turbine work is given by
WT = CP(T3 − T4)
= 1.005 (900 − 553.3)
= 348.43 kJ/kg
Net work,
= WT − WC = 32.42 kJ/kg
Power P =
∴ m =
m = = 987.05 kg/s
Example 12.8
A gas turbine plant draws in air at 1.013 bar, 10°C and has a pressure ratio of 5.5. The maximum temperature in the cycle is limited to 750°C. Compression is conducted in an uncooled rotary compressor having an isentropic efficiency of 82 per cent and expansion takes place in a turbine with an isentropic efficiency of 85 per cent. A heat exchanger with an efficiency of 70 per cent is fitted between the compressor outlet and combustion chamber. For an air flow of 40 kg/s, find the (i) overall efficiency of cycle, (ii) turbine output, (iii) air–fuel ratio if the calorific value of fuel used is 45.22 MJ/kg.
Solution: All the processes are shown on the T-s diagram below.
Considering processes 1 and 2,
T2′ = T1
ηc =
0.82 =
= 498.85 K
Considering expansion in turbine,
T4 =
Considering turbine efficiency,
ηt =
0.85 =
T4 = 688.36 K
Considering heat exchanger efficiency,
ηHE =
0.70 =
∴ T5 = 640.98 K
Cycle efficiency is given by
η =
=
= 31%
Net work done, = WT − WC = 4751.6 kJ/kg
Output power = 1 × 4751.6
= 4751.6 kW
Making heat balance in the combustion chamber,
mf × CV = (ma + mf) Cpa
mf × 45.22 × 103 = (40 + mf) × 1.005 × (1023 − 640.98)
mf × 117.78 = 40 + mf
mf =
∴ = 116.78
Free-piston engines are typically diesel powered, opposed piston engines with mechanical synchronization of the two pistons. The synchronization mechanism did, in addition to evening out possible force differences, also drive the accessories such as fuel injection pump, oil pump and water pump. Free-piston gas generators were considered for use in large-scale power plants, and at a later stage for vehicle propulsion in the late 1940s. General Motors and Ford Motor Company had working prototypes of these engines aimed for vehicle propulsion. Larger free-piston gas generators were installed in a number of stationary power plants and in some marine installations.
In a free-piston engine, the piston is ‘free’ and its motion is not restricted by the position of a rotating crankshaft, unlike in a conventional engine. The motion is determined by the interaction between the gas and load forces acting upon it. Because of this, a free-piston engine offers (i) variable stroke length, (ii) the need for active control of piston motion, (iii) potential reductions in frictional losses and (iv) possibilities to optimize engine operation by varying compression ratio.
R. P. Pescara [2] was the first to invent a free-piston engine with his patent dating from 1928. Free-piston engines may be classified as single, dual, opposed piston and gas generators. A brief account of these engines is discussed further.
1. Single piston
A single piston free-piston engine is shown in Figure 12.25. This engine essentially consists of three parts, namely a combustion cylinder, a load devic, and a rebound device to store the energy required to compress the next cylinder charge. The hydraulic cylinder serves the purpose of both load and rebound device. The rebound device is used to accurately control the amount of energy put into the compression process, and hence to regulate the compression ratio and stroke length. The system is simple in design but offers high controllability compared to the other free-piston engine configurations.
Fig. 12.25 Single-Piston Hydraulic Free-Piston Engine [3]
2. Dual piston
Figure 12.26 shows a hydraulic dual piston free-piston engine [4]. The dual piston engine configuration eliminates the need for a rebound device, as the (at any time) working piston provides the work to drive the compression process in the other cylinder. This allows a simple and more compact device with higher power to weight ratio.
The major drawback of this engine is that it is difficult to control of piston motion, in particular stroke length and compression ratio. This is because the combustion process in one cylinder drives the compression in the other, and small variations in the combustion will have high influence on the next compression. Experimental work with dual piston engines has reported high sensitivity to load nuances and high cycle-to-cycle variations [5, 6].
Fig. 12.26 A Hydraulic Dual Piston Free-Piston Engine [4]
3. Opposed piston
Figure 12.27 shows an opposed piston free-piston engine, with a mechanical piston synchronization mechanism. An opposed piston free-piston engine consists of two single piston units connected with a common combustion chamber. Each piston requires a rebound device, and a load device may be coupled to one or both of the pistons.
Fig. 12.27 A Hydraulic Dual Piston Free-Piston Engine
In the earlier days, these engines were used as air compressors and later as gas generators in large-scale plants, using a number of units feeding a single-power turbine.
The advantages of the opposed piston are the following:
The disadvantages of the opposed piston are the following:
Fig. 12.28 An Opposed Piston Free-Piston Gas Generator Plant
4. Gas generators
Figure 12.28 illustrates an opposed piston free-piston gas generator plant. Free-piston gas generators use free-piston engines that feed hot gases to a power turbine. The engine is used to supercharge the intake air, and the entire output work is utilized by the power turbine. In the mid-twentieth century, free-piston gas generators were used in some large-scale marine and stationary power plants. Free piston engines are started by rapidly introducing compressed air into the bounce chambers as shown in Figure 12.28. These engines were highly supercharged and operated on higher mean effective pressures than conventional diesel engines [3].
The most important advantages of free-piston gas generators are the following:
Some of the limitations of these engines are the following:
With the maturing of conventional gas turbine technology, development of the free-piston gas generator was largely abandoned in the early 1960s. [8, 9, 10]
Simple cycle gas turbine (GTs) plants using natural gas and fuel oil operate at around 33 percent and 25 per cent efficiency, respectively, major part of the heat being wasted as thermal energy in the hot exhaust gases.
Combining of multiple thermodynamic cycles to generate power, overall plant efficiency can be increased up to 60 per cent by using a heat recovery steam generator (HRSG). The HSRG captures heat from high-temperature exhaust gases to generate steam, which is then supplied to a steam turbine to generate additional electric power. The cycle working under this principle is known as combined cycle. In most of the instance a combined cycle power plant utilizes gas turbines in conjunction with a steam turbine and is called a combined cycle gas turbine (CCGT) plant. Different configurations of CCGT power plants are in use where each GT has its own associated HRSG, and multiple HRSGs supplying steam to one or more steam turbines. For example, in a plant with a 3 × 1 configuration, three GT/HRSG trains supply to one steam turbine. Similarly, there can be 1 × 1, 2 × 1 or 4 × 1 arrangements also. The steam turbine capacity is decided to match the number and capacity of supplying GTs/HRSGs. These types of power plants are being installed in increasing numbers round the world where there is access to substantial quantities of natural gas.
The HRSG is basically a heat exchanger popularly known as a boiler, or comprises a series of heat exchangers. It generates steam for the steam turbine exchanging heat from the hot exhaust gas flow from a gas turbine through heat exchanger tube banks. The tubes are arranged in sections, or modules also known as economizers, evaporators, superheater/reheater and preheaters. The fluid circulation in HRSG could be either natural or forced circulation using pumps. Saturated steam from the steam drums or once-through system is passed through superheater or reheater tubes to superheat the steam. The superheated steam produced by the HRSG is supplied to the steam turbine where it expands through the turbine blades, imparting rotation to the turbine shaft. The energy delivered to the generator coupled to the drive shaft is converted into electricity. After exiting the steam turbine, the steam condenses in a condenser and fed back to the HRSG. Figure 12.29 shows a schematic diagram of a combined cycle gas turbine plant.
Depending on the exhaust gas characteristics HSRGs are designed and configurations, steam requirements, etc., are decided later. Due to the high temperature of exhaust gases available at the gas turbine exit (600°C), GTs are designed to produce steam at multiple pressure levels (high-pressure steam in a large CCGT plant can reach up to 110 bar) to optimize energy recovery. Generally, three sets of heat exchanger modules – one each for high pressure (HP) steam, intermediate pressure (IP) steam, and low pressure (LP) steam – are used for this purpose.
The HRSGs present operational constraints on the CCGT power plant owing to their location, directly downstream of the gas turbines. Due to the changes in temperature and pressure of the exhaust gases thermal and mechanical stresses are set up.
Fig. 12.29 Combined Cycle Power Plant
When CCGT power plants are operated under fluctuating load conditions, characterized by frequent starts up and shut downs or when operating under part-load conditions, thermal stresses developed could cause damage to some components of the HRSG. The HP steam drum and superheater headers are subjected to the highest exhaust gas temperatures, and hence are more prone to reduced mechanical life. Some important design and operating considerations are the following:
In this system, an open-circuit gas turbine has a compressor, a combustor and a turbine. For this type of cycle, the input temperature to turbine and the output temperature of flue gases are very high. This high-temperature flue gases have heat energy high enough to provide heat for a second cycle that uses steam as the working medium, that is, thermal power plant. Figure 12.30 shows the working principle of combined cycle gas turbine (CCGT) plant. Different components of the plant are discussed further in detail.
Fig. 12.30 Working Principle of Combined Cycle Gas Turbine Plant
1. Air Inlet system
Air is drawn though the large air inlet section where it is cleaned, cooled and controlled. Majority of all heavy-duty gas turbines are designed to operate under a wide variety of climatic and environmental conditions due to inlet air filtration systems. These filtration systems are specifically designed to suit the plant location. Under normal operating conditions, the inlet system has the capability to process the air by removing contaminants to levels below those that are harmful to the compressor and turbine. In general, the incoming air may have contaminants in solid, liquid and gaseous states in addition to corrosive components. Gaseous contaminants include ammonia, chlorine, hydrocarbon gases, sulfur in the form of H2S, SO2, discharge from oil cooler vents, etc. Some of the liquid contaminants include chloride salts dissolved in water (sodium, potassium), nitrates, sulfates and hydrocarbons, etc. Solid contaminants may include sand, alumina and silica, rust, dust particles, alumina and silica, calcium sulfate, ammonia compounds from fertilizer and animal feed operations, airborne seeds, etc. In addition to these, some corrosive agents such as chlorides, nitrates and sulfates may also deposit on compressor blades inducing stress corrosion attack and/or cause corrosion pitting. Alkali metals such as sodium and potassium may also combine with sulfur to form a highly corrosive agent that may attack portions of the hot gas path. These contaminants are removed by passing through various types of filters. Gas phase contaminants such as ammonia or sulfur that cannot be removed by filtration are removed based on special methods.
2. Turbine system
The purified air is then compressed and mixed with natural gas and ignited in the combustion chamber after injecting the fuel. The high-pressure gas stream generated in the combustion chamber expands in the turbine and spins the turbine rotor and a generator, producing electricity. Heat of the gas turbine's exhaust is further passed through the heat recovery steam generator (HRSG), where live steam at temperature between 420°C and 580°C is generated, which is used as a working fluid in the secondary circuit.
3. Heat recovery steam generator
In heat recovery steam generator (HRSG), heat exchange takes place between the highly purified water flowing in tubes and the hot flue gases surrounding them, generating steam. As explained earlier, steam expands in the turbine to run the turbine rotor and hence a coupled generator, to produce electricity. The hot gases leave the HRSG at around 140°C before being discharged into the atmosphere. The steam condensing and water system in this circuit are similar to that in a typical thermal power plant. The HRSG takes more time to warm up from cold conditions compared to hot conditions.
The combined cycle system may have single-shaft and multi-shaft configurations. A single-shaft system consists of a gas turbine, a steam turbine, a generator and a heat recovery steam generator (HRSG). The gas turbine and steam turbine are coupled to the single generator on a single shaft. In a multi-shaft system, one or more gas turbine-generators and HRSGs are used to supply steam through a common header to a separate single-steam turbine generator. Overall investment on a multi-shaft system is about 5 per cent higher compared to a single-shaft system. The major disadvantage of multi-shaft system is that the number of steam turbines, condensers and condensate systems, cooling towers and circulating water systems also proportionately increases to match the number of gas turbines.
Roughly, the steam turbine cycle produces one-third of the power and gas turbine cycle produces two-thirds of the power output of the CCGT. By combining both gas and steam cycles, high input temperatures and low output temperatures can be achieved. The efficiency of the cycles adds because they are powered by the same fuel source. To increase the power system efficiency, it is necessary that the HRSG be optimized, which serves as the critical link between the gas turbine cycle and the steam turbine cycle with the objective of increasing the steam turbine output.
Overall efficiency of the combined cycle power plant depends on the performance of HRSG. There are instances of electric efficiency of a new combined cycle power station reaching 58 percent at continuous output. In addition, combined cycle units may be utilized to deliver low temperature heat energy for industrial processes, district heating and other uses. This is called cogeneration, and such power plants are of then referred to as a combined heat and power (CHP) plant.
The efficiency of CCGT is increased by supplementary firing and blade cooling. A gas turbine cooling air (TCA) cooler, with a heat exchanger using feed water, and a fuel gas heater (FGH) were also used to further enhance the efficiency of the plant in Kawasaki Thermal Power Station. This minimized the loss of heat energy allowing the plant to achieve higher thermal efficiency, outperforming conventional combined cycle plants. In this plant, supplementary firing was arranged at HRSG and in gas turbine a part of the compressed air flow bypasses to cool the turbine blades.
The turbines used in combined cycle plants are commonly fuelled with natural gas, and it is more versatile than coal or oil and can be used in 90 per cent of energy applications. Combined cycle plants are usually powered by natural gas, although fuel oil, synthesis gas or other fuels can be used.
In order to control the emission, different tools and techniques are used, namely, a selective catalytic reduction (SCR) system, aqueous ammonia solution, a low NOx combustor and a dry NOx removal apparatus, as discussed below:
1. Selective catalytic reduction
To control the emissions in the exhaust gas so that it remains within permitted levels as it enters the atmosphere, the exhaust gas passes though two catalysts located in the HRSG. One catalyst controls carbon monoxide (CO) emissions, whereas the other catalyst controls oxides of nitrogen, (NOx) emissions.
Advantages
Disadvantages
Consider a simple combined cycle plant, the gas turbine drives one electric generator and the steam turbine runs another, as illustrated in Figure 12.31. For the analysis purpose, let us ignore the losses in the heat exchanger.
Fig. 12.31 Thermodynamic Analysis of a Simple Combined Cycle Plant
Let efficiency of the gas turbine cycle (topping cycle)
inlet temperature of gas in gas turbine cycle (topping cycle)
heat rejected in gas turbine cycle (topping cycle)
efficiency of the steam turbine cycle (bottoming cycle)
inlet temperature of steam in the steam turbine cycle (bottoming cycle)
heat rejected in the steam turbine cycle (bottoming cycle)
Efficiency of the topping plant is given by
Efficiency of the topping plant is given by
Combined cycle efficiency is given by
=
If there are n number of cycles in series, then combined cycle efficiency is given by
Or
Considering the gas turbine cycle (topping cycle)
Work or power delivered by the steam turbine plant is given by
Considering the exhaust of the turbine, we have
Work or power delivered by the steam turbine plant is given by
Total power delivered by the steam and gas turbine is given by
Figure 12.32 shows the plot of v/s for various values of combined cycle efficiency, The shaded rectangle in this graph illustrates that overall efficiencies above 0.50 are possible with as low as 0.20 if the corresponding is at least 0.38. With a steam turbine efficiency of 0.32 and a gas turbine efficiency of 0.42, the combined cycle efficiency is = 0.60. If the steam turbine efficiency is 0.40, then = 0.64.
Fig. 12.32 Plot of v/s for Various Values of Combined Cycle Efficiency [11]
Figure 12.33 shows the variation of efficiency of gas turbine, steam turbine and combined cycle plant with gas turbine exhaust temperature, T2. It is evident from the plot that combined cycle offers best and highest efficiency compared to GT and ST plants as turbine exhaust temperature also increases.
Fig. 12.33 Variation of Efficiency of Various Cycles with Gas Turbine Exhaust Temperature, T2 Source: Kehlhofer, R., R. Bachmann, H. Nielsen, and J. Warner, 1999, Combined Cycle Gas and Steam Turbine Power Plants, 2nd edition. Tulsa, OK: PennWell.
Figure 12.34 shows typical layout of a gas turbine plant. The air filler is used to clean the air. The air leaving the air filler flows to the LP compressor. The compressed air then flows through the intercooler and then it enters the high-pressure compressor. The air leaving the air compressor flows through the heat exchanger and the hot air flows to the combustion chamber. Products of combustion then enter in to low-pressure turbine, where it expands doing useful work.
Fig. 12.34 Layout of Gas Turbine Plant
Identify the correct statements using the code given below:
Select the correct statements using the codes given below: